Question
A saturated solution, prepared by dissolving $CaF _{2(s)}$ in water, has $\left[ Ca ^{2+}\right]=3.3 \times 10^{-4} M$ What is the $K _{\text {sp }}$ of $CaF _2$ ?

Answer

$C a F_{2(s)} \rightleftharpoons C a_{(a q)}^{2+}+2 F_{(a q)}^{-}$
${\left[FF^{-}\right]=2\left[Ca^{2+}\right]}$
$=2 \times 3.3 \times 10^{-4} M$
$=6.6 \times 10^{-4} M$
$K_{sp}=\left[Ca^{2+}\right]\left[FF^{-}\right]^2$
$=\left(3.3 \times 10^{-4}\right)\left(6.6 \times 10^{-4}\right)^2$
$=1.44 \times 10^{-4}$

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