A simple harmonic motion is represented by $y\, = 5\,(\sin \,3\pi t\, + \,\sqrt 3 \,\cos \,3\pi t)\,cm$ The amplitude and time period of the motion are
JEE MAIN 2019, Medium
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$y=5(\sin 3 \pi t+\sqrt{3} \cos 3 \pi t) \mathrm{cm}$
$\Rightarrow \quad y=10 \sin (3 \pi t+\phi)$
$\Rightarrow A=10 \mathrm{cm}$
$\Rightarrow \quad T=\frac{2}{3} \sec$
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