MCQ
A simple pendulum executing $S.H.M.$ is falling freely along with the support. Then
- AIts periodic time decreases
- BIts periodic time increases
- ✓It does not oscillate at all
- DNone of these
✓
Answer
Correct option: C.
It does not oscillate at all
c
(c) $ T = 2\pi \sqrt{\frac{l}{g}}$; for freely falling system effective $g = 0$
so $T = \infty $ or $n = 0$
It means that pendulum does not oscillate at all.
(c) $ T = 2\pi \sqrt{\frac{l}{g}}$; for freely falling system effective $g = 0$
so $T = \infty $ or $n = 0$
It means that pendulum does not oscillate at all.
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