A simple pendulum executing $S.H.M.$ is falling freely along with the support. Then
A
Its periodic time decreases
B
Its periodic time increases
C
It does not oscillate at all
D
None of these
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C
It does not oscillate at all
c (c) $ T = 2\pi \sqrt{\frac{l}{g}}$; for freely falling system effective $g = 0$
so $T = \infty $ or $n = 0$
It means that pendulum does not oscillate at all.
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