Question
A simple pendulum is inside a spacecraft. What will be its periodic time?

Answer

Periodic time of simple pendulum is given by, $T=2 \pi \sqrt{\frac{ L }{ g }}$
But, inside a spacecraft, acceleration due to gravity is zero.
$ \therefore T =2 \pi \sqrt{\frac{ L }{0}}$
$\therefore T =\infty $
$\therefore$ The time period of a simple pendulum inside a spacecraft is infinite.

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