Question
A small block of mass 'm' is pressed against a horizontal spring fixed at one end to compress the spring through 5.0cm. When released the block moves horizontally till it leaves the spring. Where will it hit the ground at a distance 2m below the slab?

$[\text{k}=100\frac{\text{N}}{\text{m}}=100\text{g}]$

Answer

Here $\frac{1}{2}\text{kx}^2=\frac{1}{2}\text{m}\upsilon^2$
$\upsilon=\sqrt{\frac{\text{k}}{\text{m}}\text{x}^2}$
$=\sqrt{\frac{100}{100}\times\frac{25\times10^{-4}}{10^{-3}}}\text{ms}^{-1}$
$=\sqrt{2.5}\text{ms}^{-1}$
Height = 2m; $\text{t}=\sqrt{\frac{2\text{h}}{\text{g}}}$
$=\sqrt{0.4}\text{ms}^{-1}$

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