Question
A soft drink is available in two packs-
$(i)$ a tin can with a rectangular base of length $5\ cm$ and width $4\ cm$, having a height of $15\ cm$ and
$(ii)$ a plastic cylinder with circular base of diameter $7\ cm$ and height $10\ cm$,
Which container has greater capacity and by how much?

Answer

Given: The tin can will be cubical in shape.
 Length $(L)$ of tin can $= 5cm$
Breadth $(B)$ of tin can $= 4\ cm$
Height $(H)$ of tin can $= 15\ cm$
Capacity of the tin can
$= l \times b \times h = (5 \times 4 \times 15)cm^3$
Radius $(R)$ of the circular end of the plastic cylinder
​​​​​​​$\frac{7}{2}\text{cm}=3.5\text{cm}$
Height $(H)$ of plastic cylinder $= 10\ cm$
Capacity of plastic cylinder $=\pi\text{R}^2\text{H}$
$=\frac{22}{7}\times(3.5)^5\times10\text{cm}^3=385\text{cm}^3$
Therefore, the plastic cylinder has greater capacity.
Difference in capacity $= (385 - 300)cm^3= 85cm^3​​​​​​​$​​​​​​​

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