Question
A solid metallic hemisphere of radius 8cm is melted and recasted into a right circular cone of base radius 6cm. Determine the height of the cone.

Answer


As the hemisphere is recasted into a cone. So,
Volume of cone = Volume of hemisphere
$\Rightarrow\ \ \frac{1}{3}\pi\text{r}^2\text{h}=\frac{2}{3}\pi\text{R}^3$
$\Rightarrow\ \ \text{r}^2\text{h}=2\text{R}^3$
$\Rightarrow\ \ \text{h}=\frac{2\text{R}^3}{\text{r}^2}=\frac{2\times8\times8\times8}{6\times6}=\frac{32\times8}{9}$
$=\frac{256}{9}=\frac{28.44}{}\text{cm}$
$\Rightarrow\ \ \text{h}=28.44\text{cm}.$
Hence, the height of the cone is 28.44cm.

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