Question
A sound wave in a certain fluid medium is reflected at an obstacle to form a standing wave. The distance between two successive nodes is $3.75\ cm.$ If the velocity of sound is $1500\ m/s,$ find the frequency.
✓
Answer
Data: Distance between two successive nodes =
$ \frac{\lambda}{2}=3.75 \times 10^{-2} m , v =1500 m / s$
$\therefore \lambda=7.5 \times 10^{-2} m$
$v = n \times \lambda$
$\therefore n =\frac{1500}{7.5 \times 10^{-2}}=20 kHz$
$ \frac{\lambda}{2}=3.75 \times 10^{-2} m , v =1500 m / s$
$\therefore \lambda=7.5 \times 10^{-2} m$
$v = n \times \lambda$
$\therefore n =\frac{1500}{7.5 \times 10^{-2}}=20 kHz$
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