Question
A source of sound with adjustable frequency produces 2 beats per second with a tuning fork when its frequency is either 476Hz or 480Hz. What is the frequency of the tuning fork?
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Answer
Given, First Frequency f1 = 476Hz Second frequency f2 = 480Hz Number of beats produced per second by the tuning fork m = 2 As the tuning fork produces 2 beats, its frequency should be an average of two. This is given by,
$\text{f}=\frac{(\text{f}_1+\text{f}_2)}{2}$
$\text{f}=\frac{(476+480)}{2}=478\text{Hz}$
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