MCQ
A square planar complex is formed by hybridisation of which atomic orbitals
- A$s,\,\,{p_x},\,\,{p_y},\,\,{d_{yz}}$
- ✓$s,\,\,{p_x},\,\,{p_y},\,\,{d_{{x^2} - {y^2}}}$
- C$s,\,\,{p_x},\,\,{p_{y,\,\,}}{d_{{z^2}}}$
- D$s,\,\,{p_y},\,\,{p_z},{d_{xy}}$
✓
Answer
Correct option: B.
$s,\,\,{p_x},\,\,{p_y},\,\,{d_{{x^2} - {y^2}}}$
(b)For square planar geometry hybridization is $ds{p^2}$involving $s$,${p_x},\,{p_y}$ and ${d_{{x^2} - }}_{{y^2}}$ orbital.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In the following reversible reaction $2S{O_2} + {O_2}$ $\rightleftharpoons$ $2S{O_3} + Q$ $Cal$ Most suitable condition for the higher production of $S{O_3}$ is
→The $IUPAC$ name of (figure) is
→The element of ${s^2}{p^2}$ configuration is of ..... group
→Which statement is false for the balanced equation given below ?
→$CS_2 + 3O_2 \,\,\to \,\, 2SO_2 + CO_2$
Which is not formed in the given reaction
Oxidation number of $Mn$ in ${K_2}Mn{O_4}$ and $MnS{O_4}$ are respectively
→Which oribital notation does not have spherical node
In the following reaction:
→$HC \equiv CH\,\xrightarrow[{H{g^{2 + }}}]{{{H_2}S{O_4}}}\,'P'$
Product $'P'$ will not give
If ${10^{21}}$ molecules are removed from $200\,mg $ of $C{O_2}$, then the number of moles of $C{O_2}$ left are ..........$\times {10^{ - 3}}$
→The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms?