A steady current (I_1) flows through a long straight wire. Anothe… - Vidyadip

Question

A steady current $(I_1)$ flows through a long straight wire. Another wire carrying steady current $(I_2)$ in the same direction is kept close and parallel to the first wire. Show with the help of a diagram how the magnetic field due to the current $I_1$ exerts a magnetic force on the second wire. Write the expression for this force.

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Answer

$\text{F}_{12} = \text{I}_{2}\text{IB}_{1}$
$\text{F}_{12} = \frac{\mu_{o}\text{I}_{1}\text{I}_{2}}{2\pi\text{d}}\text{l}$.

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