MCQ
A storage cell is charged by 5 amp D.C. for 18 hours. Its strength after charging will be
  • A
    $18 \mathrm{AH}$
  • B
    $5 \mathrm{AH}$
  • C
    $90 \mathrm{AH}$
  • $15 \mathrm{AH}$

Answer

Correct option: D.
$15 \mathrm{AH}$
(d) $6 \Omega$ and $6 \Omega$ are in series, so effective resistance is $12 \Omega$ which is in parallel with $3 \Omega$, so$\begin{aligned}& \frac{1}{R}=\frac{1}{3}+\frac{1}{12}=\frac{15}{36} \Rightarrow R=\frac{36}{15} \\& \therefore I=\frac{V}{R}=\frac{4.8 \times 15}{36}=2 \mathrm{~A}\end{aligned}$

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