Question
A string of length $2 m$ is fixed at both ends. If this string vibrates in its fourth normal mode with a frequency of $500 Hz$ then the waves would travel on its with a velocity of ..... $m/s$
✓
Answer
(c) For string $\lambda = \frac{{2l}}{p}$
where $p =$ No. of loops = Order of vibration
Hence for forth mode $p = 4$
where $p =$ No. of loops = Order of vibration
Hence for forth mode $p = 4$
==> $\lambda = \frac{l}{2}$
Hence $v = n\lambda = 500 \times \frac{2}{2} = 500\,Hz$
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