Question
A substance may be athermanous or diathermanous for certain wavelength ranges while good absorber for other wavelength ranges. Explain.

Answer


For interaction of light with matter, it is necessary to consider the atomic nature of matter. Interaction of an atom with light depends on the frequency or equivalently on the photon energy.An atom absorbs light if the photon's energy equals one of the excitation energies of the atom. In the dense atomic neighbourhood of ordinary gases at pressures above $100 \mathrm{~Pa}$, solids and liquids, the discrete atomic energy states widen into bands. Thus, bulk matter, depending on its nature, possesses absorption bands in specific regions within the electromagnetic frequency spectrum.
Radiant energy of other frequencies is elastically scattered so that the material is transparent at these frequencies.
[Note: Colourless, transparent materials have their absorption bands outside the visible region of the spectrum, which is why they are, in fact, colourless and transparent. Glasses have absorption bands in the ultraviolet region $(\sim 100 \mathrm{~nm}-200 \mathrm{~nm})$, where they become opaque. At even longer wavelengths of radiowaves glass is again transparent. In comparison, a stained glass has absorption band in the visible region where it absorbs out a particular range of frequencies, transmitting the complementary colour. Semiconductors, such as ZnSe, $\mathrm{CdTe}, \mathrm{GaAs}$ and $\mathrm{Ge}$, which are opaque in the visible region of the spectrum are highly transparent in the infrared region $(2 \mu \mathrm{m}$ to $30 \mu \mathrm{m})$.]

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