MCQ
A suitable unit for gravitational constant is
  • A
    $kg{\rm{ - }}\,m\;{\sec ^{ - 1}}$
  • B
    $N\;{m^{ - 1}}\sec $
  • $N\,\,{m^2}\,k{g^{ - 2}}$
  • D
    $kg\,m\,{\sec ^{ - 1}}$

Answer

Correct option: C.
$N\,\,{m^2}\,k{g^{ - 2}}$
c
(c) $F = \frac{{G{m_1}{m_2}}}{{{d^2}}};$

$\therefore $ $G = \frac{{F{d^2}}}{{{m_1}{m_2}}} = N{m^2}/k{g^2}$

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