A thermocouple of negligible resistance produces an $e.m.f.$ of $40\,\mu V{/^o}C$ in the linear range of temperature. A galvanometer of resistance $10\; ohm$ whose sensitivity is $1\;\mu A/div$, is employed with the thermocouple. The smallest value of temperature difference that can be detected by the system will be
AIPMT 2011, Medium
Download our app for free and get startedPlay store
(d) For minimum deflection of 1 divison require current $=1 \mu A$

Voltage required $=i R=1 \times 10=10 \mu V$

$\therefore 40 \mu V \cong 1^{\circ} C$

$10 \mu V \cong \frac{1}{(4)^{\circ}} C$

$=2.50^{\circ} C$

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    The electric current passing through a metallic wire produces heat because of
    View Solution
  • 2
    Variation of current and voltage in a conductor has been shown in the diagram below. The resistance of the conductor is. ........... $ohm$
    View Solution
  • 3
    When electric bulbs of same power, but different marked voltage are connected in series across the power line, their brightness will be :
    View Solution
  • 4
    Calculate the amount of charge flowing in $2$ minutes in a wire of resistance $10$ $\Omega$ when a potential difference of $20\,V$ is applied between its ends ............ $C$
    View Solution
  • 5
    Two light bulbs in the circuit have rating $A\,[24\ V, 48\,W]$ and $B\,[24\ V, 36\,W]$ as shown.
    View Solution
  • 6
    The total momentum of electrons in a straight wire of copper of length $1\, metre$ carrying a current of $16\, A$ is
    View Solution
  • 7
    In the circuits shown below, the readings of the voltmeters and the ammeters will be
    View Solution
  • 8
    How many $60 \,W$ bulbs may be safely run on $220 \,V$ using a $5 \,A$ fuse is .........
    View Solution
  • 9
    The galvanometer deflection, when key $K_1$ is closed but $K_2$ is open, equals $\theta_0$ (see figure). On closing $K_2$ also and adjusting $R_2$ to $5\,\Omega $ , the deflection in galvanometer becomes $\frac{{\theta _0}}{5}$. The resistance of the galvanometer is, then, given by [Neglect the internal resistance of battery]: .................. $\Omega$
    View Solution
  • 10
    For the given circuit the current through battery of $6\,V$ just after closing the switch ' $S$ ' will be$.......A$.
    View Solution