Question
A thin circular ring of mass M and radius r is rotating about its axis with an angular speed $\omega.$ Two particles having mass m each are now attached at diametrically opposite points. The angular speed of the ring will become:
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$\frac{\omega\text{M}}{\text{M}+\text{m}}$
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$\frac{\omega\text{M}}{\text{M}+\text{2m}}$
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$\frac{\omega(\text{M}-\text{2m})}{\text{M}+\text{2m}}$
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$\frac{\omega(\text{M}+\text{2m})}{\text{M}}$
