A trend common to both groups I and VII elements in the periodic … - Vidyadip

MCQ

A trend common to both groups $I$ and $VII$ elements in the periodic table as atomic number increases is

A
Oxidising power increases
✓
Atomic radius increases
C
Maximum valency increases
D
Reactivity with water increases

✓

Answer

Correct option: B.

Atomic radius increases

b
(b) Atomic radius increases as no. of shells increases.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 3. Classification of elements and periodicity in properties→3. Classification of elements and periodicity in properties — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

A chemical reaction is at equilibrium when

A solution whose $ pH$ value is less than $7$ will be

When enthalpy and entropy change for a chemical reaction are $ - 2.5\, \times {10^3}\,cal$ and $7.4\,cal$ ${\deg ^{ - 1}}$ respectively. Predict the reaction at $298\,K$ is

$K_{sp}$ for $BaSO_4$ at $25\,^oC$ is $1.1 \times 10^{-10}$ . To make the new solubility equal to $1.1 \times 10^{-8}$ , it is necessary to use the solution of $Na_2SO_4$ of the following concentration .......$M$

If $Ag^+ + NH_3 \rightleftharpoons [Ag(NH_3)]^+$ ;

$K_1 = 1.6 \times 10^3$ and

$[Ag(NH_3)]^+ + NH_3 \rightleftharpoons [Ag(NH_3)_2]^+$ ;

$K_2 = 6.8 \times 10^3$ .

Then formation constant of $[Ag(NH_3)_2]^+$ is :

Which of the following is the least $ random$ state of water

Species isoelectronic with $BF_3$ would be

The radius of second Bohr's orbits for hydrogen atoms is :
$\text{h}=6.6262\times10^{-34}\text{Js},\text{m}_\text{e}$
$=9.109\times10^{-31}\text{kg},\text{e}_{\text{change}}$
$=1.6021\times10^{19\text{C}}$

Which of the following is the correct order of ionic radii

Which of the following statement is not correct about diborane?