MCQ
A uniform chain of length $L$ changes partly from a table which is kept in equilibrium by friction. The maximum length that can withstand without slipping is $/$, then coefficient of friction between the table and the chain is
  • A
    $\frac{l}{L}$
  • B
    $\frac{l}{L+l}$
  • $\frac{l}{L-l}$
  • D
    $\frac{L}{L+l}$

Answer

Correct option: C.
$\frac{l}{L-l}$
(c) $\quad \mu=\frac{\text { Lenght of chain hanging from the table }}{\text { Lenght of chain lyingon the table }}=\frac{l}{L-l}$

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