$A$ uniform copper wire carries a current $i$ amperes and has $p$ carriers per meter$^3$. The length of the wire is $\lambda$ meters and its cross-section area is $s$ meter $^2$. If the charge on a carrier is $q$ coulombs, the drift velocity in $ms^{-1}$ is given by
Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1The equivalent resistance between the points $A$ and $D$ ................ $\Omega$View Solution
- 2A dry cell has an $e.m.f.$ of $1.5\, V$ and an internal resistance of $0.05\,\Omega $. The maximum current obtainable from this cell for a very short time interval is ................... $A$View Solution
- 3A wire $50\, cm$ long and $1\;mm^2$ in cross -section carries a current of $4\; A$ when connected to a $2\; V$ battery. The resistivity of the wire isView Solution
- 4$A$ current passes through a wire of nonuniform cross section. Which of the following quantities are independent of the cross-section?View Solution
- 5In the following diagram, the lengths of wires $A B$ and $B C$ are equal, but the radius of wire $A B$ is double that of $B C$. The ratio of potential gradient on wires $A B$ and on $B C$ will be (wires are made of same material)View Solution
- 6In the circuit shown in the figure $K_1$ is open. The charge on capacitor $C$ in steady state is $q_1$. Now key is closed and at steady state charge on $C$ is $q_2$. The ratio of charges $q_1/q_2$ isView Solution
- 7If the ammeter in the given circuit reads $2\, A$, the resistance $R$ is ............ $ohm$View Solution
- 8In a meter bridge, the wire of length $1\, m$ has a nonuniform cross-section such that, the variation $\frac{{dR}}{{d\ell }}$ of its resistance $R$ with length $\ell $ is $\frac{{dR}}{{d\ell }} \propto \frac{1}{{\sqrt \ell }}$ Two equal resistances are connected as shown in the figure. The galvanometer has zero deflection when the jockey is at point $P$. What is the length $AP$ ? ................ $m$View Solution
- 9Consider a block of conducting material ofresistivity '$\rho$' shown in the figure. Current '$I$' enters at '$A$' and leaves from '$D$'. We apply superp osition principle to find voltage '$\Delta V$ ' developed between '$B$' and '$C$'. The calculation is done in the following steps:View Solution
$(i)$ Take current '$I$' entering from '$A$' and assume it to spread over a hemispherical surface in the block.
$(ii)$ Calculatefield $E(r)$ at distance '$r$' from $A$ by using Ohm's law $E = \rho j$, where j is the current per unit area at '$r$'.
$(iii)$ From the '$r$' dependence of $E(r)$, obtain the potential $V(r)$ at $r$.
$(iv)$ Repeat $(i), (ii)$ and $(iii)$ for current '$I$' leaving '$D$' and superpose results for '$A$' and '$D$'.For current entering at $A$, the electric field at a distance '$r$'
from $A$ is
- 10In the following $'I'$ refers to current and other symbols have their usual meaning, Choose the option that corresponds to the dimensions of electrical conductivityView Solution