A uniform rod of length $2.0 \,m$ is suspended through an end and is set into oscillation with small amplitude under gravity. The time period of oscillation is approximately .... $\sec$
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(d)This is the special case of physical pendulum and in this case $T = 2\pi \sqrt {\frac{{2l}}{{3g}}} $
$ \Rightarrow $ $T = 2 \times 3.14\sqrt {\frac{{2 \times 2}}{{3 \times 9.8}}} = 2.31\sec \approx 2.4\sec $
$ \Rightarrow $ $T = 2 \times 3.14\sqrt {\frac{{2 \times 2}}{{3 \times 9.8}}} = 2.31\sec \approx 2.4\sec $
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