$(a)\ I_{xR}/I_{xS} <1;\ (b)\ I_{yR}/I_{yS} >1; \ (c)\ I_{zR}/I_{zS} >1$
$\mathrm{I}_{\mathrm{XR}}=\frac{\mathrm{Mb}^{2}}{12}, \mathrm{I}_{\mathrm{YR}}=\frac{\mathrm{Ma}^{2}}{12}, \mathrm{I}_{\mathrm{ZR}}=\frac{\mathrm{M}\left(\mathrm{a}^{2}+\mathrm{b}^{2}\right)}{12}$
$\mathrm{I}_{\mathrm{XS}}=\frac{\mathrm{Mc}^{2}}{12}, \mathrm{I}_{\mathrm{YS}}=\frac{\mathrm{Mc}^{2}}{12}, \mathrm{I}_{\mathrm{zs}}=\frac{\mathrm{Mc}^{2}}{6}$
$\frac{\mathrm{I}_{\mathrm{ZR}}}{\mathrm{I}_{\mathrm{ZS}}}=\frac{1}{2}\left(\left(\frac{\mathrm{a}}{\mathrm{c}}\right)^{2}+\left(\frac{\mathrm{b}}{\mathrm{c}}\right)^{2}\right)$
$=\frac{1}{2}\left(\left(\frac{\mathrm{a}}{\mathrm{c}}\right)^{2}+\left(\frac{\mathrm{c}}{\mathrm{a}}\right)^{2}\right)$
$\frac{I_{\mathbb{Z R}}}{I_{Z S}}>1$
$x+\frac{1}{x}>2$ if $x>0$
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Reason : Resistance of wire is proportional ot resistivity of material.