Question
A unit vector along the direction $\hat{\text{i}}+\hat{\text{j}}+\hat{\text{k}}$ has a magnitude:

  1. $\sqrt{3}$

  2. $\sqrt{2}$

  3. $1$

  4. $0$

Answer

  1. $1$

Solution:

A unit vector along any direction always has magnitude.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

From a set of 100 cards numbered 1 to 100, one card is drawn at randow. The probability number obtained on the card is divisible by 6 or 8 but not by 24 is
  1. $\frac{6}{25}$
  2. $\frac{1}{4}$
  3. $\frac{1}{6}$
  4. $\frac{2}{6}$
If $\int_0^{\frac{\pi}{4}} \frac{\sin ^2 x}{1+\sin x \cos x} d x=\frac{1}{a} \log _e\left(\frac{a}{3}\right)+\frac{\pi}{b \sqrt{3}}$, where a, $\mathrm{b} \in \mathrm{N}$, then $\mathrm{a}+\mathrm{b}$ is equal to ....................
Let $k_1$, $k_2$ be the maximum and minimum values of $k$ for which the system of equations given by

$x + ky = 1$ ; $kx + y = 2$;  $x + y = k$  are consistent then $k_1^2 + k_2^2$ is equal to

If $f(x) = {{{x^2} - 1} \over {{x^2} + 1}}$, for every real number $x,$ then the minimum value of $f$
The point which does not lie in the half plane $2 x+3 y-12 \leq 0$ is
If $f(x) \, \& \,g(x)$ are inverse functions of each other such that $f(1) = 3\, \& \,f(3) = 1,$ then $\int\limits_1^3 {\left( {g(x) + \frac{x}{{f'\left( {g\left( x \right)} \right)}}} \right)} dx$ is equal to -
The value of the function $(x - 1){(x - 2)^2}$ at its maxima is
Let $a, b$ and $c$ be distinct positive numbers. If the vectors $a \hat{i}+a \hat{j}+c \hat{k}, \hat{i}+\hat{k}$ and $c \hat{i}+c \hat{j}+b \hat{k}$ are co-planar, then $\mathrm{c}$ is equal to:
If $\mid\text{a}\mid=4$ and $-3\underline{<}\lambda\underline{<}2$ then the range of $\mid\lambda\text{a}\mid$ is:
  1. [0, 8]
  2. [-12, 8]
  3. [0, 12]
  4. [8, 12]
If $M = \left[ {\begin{array}{*{20}{c}}1&2\\2&3\end{array}} \right]$ and ${M^2} - \lambda M - {I_2} = 0$, then $\lambda = $