A weightless spring which has a force constant oscillates with frequency $n$ when a mass $m$ is suspended from it. The spring is cut into two equal halves and a mass $2m $ is suspended from it. The frequency of oscillation will now become
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If $x=5 \sin \left(\pi t+\frac{\pi}{3}\right) \mathrm{m}$ represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are
The variation of kinetic energy $(KE)$ of a particle executing simple harmonic motion with the displacement $(x)$ starting from mean position to extreme position $(A)$ is given by
A rod of mass $m$ and length $l$ is suspended from ceiling with two string of length $l$ as shown. When the rod is given a small push in the plane of page and released time period is $T_1$ and when the rod is given a push perpendicular to plane time period of oscillation is $T_2$ . The ratio $\frac{{T_1^2}}{{T_2^2}}$ is
The force constants of two springs are ${K_1}$ and ${K_2}$. Both are stretched till their elastic energies are equal. If the stretching forces are ${F_1}$ and ${F_2}$, then ${F_1}:{F_2}$ is
A point object is kept in front of a plane mirror. The plane mirror is doing $SHM$ of amplitude $2\,cm$. The plane mirror moves along the $x-$ axis and $x-$ axis is normal to the mirror. The amplitude of the mirror is such that the object is always infront of the mirror. The amplitude of $SHM$ of the image is .... $cm$
$Assertion :$ In simple harmonic motion, the motion is to and fro and periodic
$Reason :$ Velocity of the particle $(v) = \omega \sqrt {k^2 - x^2}$ (where $x$ is the displacement).
A lift is descending with acceleration $g/3$ . What will be the time period of a simple pendulum suspended from its ceiling if its time period in staionary life is $'T'$ ?