MCQ
$(A)$ will be


- A

- B

- ✓

- D







Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
End product $(X)$ of the above reaction is
$\begin{array}{*{20}{c}}
{C{H_3} - C \equiv C - C{H_2} - \mathop C\limits_{\mathop {||}\limits_O } - Cl}
\end{array} \ \xrightarrow[{BaS{O_4}}]{{{H_2} - Pd}}$
[Given : Atomic masses : $C : 12.0 u$,$H : 1.0 u , O : 16.0 u ]$