MCQ
A wire carrying current $I$ is bent in the shape $A\,B\,C\,D\,E\,F\,A$ as shown, where rectangle $A\,B\,C\,D\,A$ and $A\,D\,E\,F\,A$ are perpendicular to each other. If the sides of the rectangles are of lengths $a$ and $b,$ then the magnitude and direction of magnetic moment of the loop $A\,B\,C\,D\,E\,F\,A\,$ is
  • A
    $\sqrt{2}$ $abI$, along $\left(\frac{\hat{j}}{\sqrt{2}}+\frac{\hat{ k }}{\sqrt{2}}\right)$
  • B
    $\sqrt{2}$ $abI,$ along $\left(\frac{\hat{j}}{\sqrt{5}}+\frac{2 \hat{k}}{\sqrt{5}}\right)$
  • C
    $abI,$ along $\left(\frac{\hat{j}}{\sqrt{2}}+\frac{\hat{k}}{\sqrt{2}}\right)$
  • D
    $abI,$ along $\left(\frac{\hat{j}}{\sqrt{5}}+\frac{2 \hat{ k }}{\sqrt{5}}\right)$

Answer

Sol. $\quad M=N I A$

$N =1$

For $ABCD$

$\overrightarrow{ M }_{1}= abI \hat{ K }$

For $DEFA$

$\overrightarrow{ M }_{2}= abI \hat{ j }$

$\overrightarrow{ M }=\overrightarrow{ M }_{1}+\overrightarrow{ M }_{2}$

$=\operatorname{ab} I (\hat{ k }+\hat{j})$

$=\operatorname{ab} I \sqrt{2}\left(\frac{\hat{j}}{\sqrt{2}}+\frac{\hat{ k }}{\sqrt{2}}\right)$

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