The products formed in the above reaction are
$(A)$ Nucleotide form from nucleoside and phosphate group by ether linkage
$(B)$ In nucleoside, nitrogenous base link with hexose sugar of $DNA$ or $RNA$
$(C)$ $DNA$ and $RNA$ are differ in only nature of sugar
$(D)$ $A = T$ and $C \equiv G$ are hydrogen bond between nitrogenous base
$\begin{align}
\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
H-O-C-C{{H}_{2}}-C{{H}_{2}}-CH-C{{O}_{2}}H \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underset{\oplus }{\mathop{N}}\,{{H}_{3}} \\
\end{matrix}\,\,\,\,\,(p{{K}_{a}}=2) \\
(p{{K}_{a}}=4)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(p{{K}_{a}}=9) \\
\end{align}$