MCQ
Above conversion can be achieved by


- AWolf-Kishner reduction.
- ✓Clemmensen reduction
- C$LiAlH_4$
- D$NaBH_4$


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$2Ph - CHO\xrightarrow{{KOH}}Ph - C{H_2}OH + PhCO_2^ - $
$C{H_3}C{H_2}OH\xrightarrow{{P + {I_2}}}A\xrightarrow[{Ether}]{{Mg}}B $ $\xrightarrow{{HCHO}}C\xrightarrow{{{H_2}O}}D,$
then compound $'D'$ is -