MCQ
Acid used for making permanent marking on the glass surface is
  • A
    $HNO_3$
  • B
    $HF$
  • C
    $HIO_3$
  • $H_2SO_4$

Answer

Correct option: D.
$H_2SO_4$
d
$HCl$ is gas at $R.T.$ (Hydrochloric acid is aqueous solution of $HCl$ which is liquid)

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Compound A formed in the following reaction reacts with B gives the product C. Find out A and B.
$CH _3- C \equiv CH + Na \rightarrow A \xrightarrow{ B } CH _3 \underset{\text { (C) }}{ C \equiv C - CH _2}-\underset{ CH _3}{ CH _2}+ NaBr$
How long a current of $3\, amp$ has to be passed through a solution of $AgNO_3$ to coat a metal surface of $80\, cm^2$ with $0.005\, mm$ thick layer? Density of $Ag$ is $10.5\, g/cm^3$ .................. $\mathrm{sec}$
Match $List-I$ with $List-II$.

Match $List-I:in\, Figure$

Lits$-II$

$(I)$ Gatterman Koch reaction

$(II)$ Etard reaction

$(III)$ Stephen reaction

$(IV)$ Rosenmund reaction

Choose the correct answer from the options given below.

The compound $A$ with following sequence of reaction gave benzoic acid.

$A\xrightarrow{NaN{{O}_{2}}/HCl}B\xrightarrow{KCN}C\xrightarrow{{{H}_{3}}{{O}^{+}}}$  benzoic acid

The compound $ A$ is

Given that the abundances of isotopes ${ }^{54} \mathrm{Fe},{ }^{56} \mathrm{Fe}$ and ${ }^{57} \mathrm{Fe}$ are $5 \%, 90 \%$ and $5 \%$, respectively, the atomic mass of $\mathrm{Fe}$ is
An organic compound contains $C = 36\% $ $H = 6\% $ and rest oxygen. Its Empirical formula is
$200\ ml$ of a mixture of $50\%\, H_2$ , $40\%\, CH_4$ and $10\%\, CO_2$ is exploded with excess of oxygen in an eudiometry tube. The resultant mixture is cooled to room temperature and is passed through $aq. KOH$ . Find volume contraction after passing through $KOH$ ................. $\mathrm{ml}$
The volume (in $mL$ ) of $0.1 \ M AgNO _3$ required for complete precipitation of chloride ions present in $30 \ mL$ of $0.01 \ M$ solution of $\left[ Cr \left( H _2 O \right)_5 Cl \right] Cl _2$, as silver chloride is close to
Consider the ions/molecule

$O _{2}^{+}, O _{2}, O _{2}^{-}, O _{2}^{2-}$

For increasing bond order the correct option is ..... .

One of the commonly used electrode is calomel electrode. Under which of the following categories calomel electrode comes ?