MCQ
Acidified $KMnO_4$ can be decolourised by
- A$SO_2$
- B$H_2O_2$
- C$FeSO_4$
- ✓All of the above
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$3MnO_4^{2-} + 2H_2O \rightleftharpoons 2MnO_4^- + MnO_2 + 4OH^-$
The reaction can go to completion by removing $OH^-$ ions by adding


