Activation energy is given by the formula - Vidyadip

MCQ

Activation energy is given by the formula

✓
$\log \frac{{{K_2}}}{{{K_1}}} = \frac{{{E_a}}}{{2.303R}}\left[ {\frac{{{T_2} - {T_1}}}{{{T_1}{T_2}}}} \right]$
B
$\log \frac{{{K_1}}}{{{K_2}}} = - \frac{{{E_a}}}{{2.303R}}\left[ {\frac{{{T_2} - {T_1}}}{{{T_1}{T_2}}}} \right]$
C
$\log \frac{{{K_1}}}{{{K_2}}} = - \frac{{{E_a}}}{{2.303R}}\left[ {\frac{{{T_1} - {T_2}}}{{{T_1}{T_2}}}} \right]$
D
None of these

✓

Answer

Correct option: A.

$\log \frac{{{K_2}}}{{{K_1}}} = \frac{{{E_a}}}{{2.303R}}\left[ {\frac{{{T_2} - {T_1}}}{{{T_1}{T_2}}}} \right]$

a
(a)It is modified form of Arrhenius equation.

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