MCQ
Adding powdered lead and iron to a solution that is $1.0 M$  in both $P{b^{2 + }}$and $F{e^{2 + }}$ions, would result a reaction, in which
  • A
    More iron and $P{b^{2 + }}$ions are formed
  • More lead and $F{e^{2 + }}$ions are formed
  • C
    Concentration of both $P{b^{2 + }}$and $F{e^{2 + }}$ions increases
  • D
    There is no net change

Answer

Correct option: B.
More lead and $F{e^{2 + }}$ions are formed
b
The standard reduction potential of $Pb ^{-2} \mid Pb$ electrode is $-0.126 \,V$ which less negative than the standard reduction potential of $Fe ^{2+} \mid Fe$ electrode which is $-0.44 \,V$

Hence, $Pb ^{2+}$ ions are reduced to $Pb$ and $Fe$ is oxidized to $Fe ^{2+}$.

Adding powdered $Pb$ and $Fe$ to a solution containing $1\, M$ each of $Pb ^{2+}$ and $Fe ^{2+}$ ions would result in the formation of more of $Pb$ and $Fe ^{2+}$ ions.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free