MCQ
Alcohol can be dehydrated by:
  • A
    $\ce{(CH_3​CO)_{2​}O}$
  • B
    $\ce{(CH_3​)_2​SO_{4​}}$
  • C
    $HI/P$
  • D
    $Anhy\ \ce{ZnCl_{2​/}} \Delta$

Answer

$\text{R}-\text{CH}_2-\text{OH}\xrightarrow{\text{Anhy Zncl}_2{\Delta}}\text{R}=\text{CH}_2$
 

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