MCQ
Alcohols having molecular formula $C _3 H _8 O$, can be :
- AOnly primary
- BOnly secondary
- ✓Primary and secondary
- DPrimary, secondary and tertiary
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$Zn \,|\,ZnSO_4\,(0.01\,M)\,||\,CuSO_4\,(1.0\, M)\,|\,Cu,$
the $emf$ of this Daniell cell is $E_1.$ When the concentration of $ZnSO_4$ is changed to $1.0\, M$ and that of $CuSO_4$ changed to $0.01\, M,$ the $emf$ changes to $E_2.$ Fromthe followings, which one is the relationship between $E_1$ and $E_2$ ? (Given, $RT/F = 0.059$)

(Given atomic number: $\mathrm{Sc}: 21, \mathrm{Ti}: 22, \mathrm{~V}: 23$, $\mathrm{Cr}: 24, \mathrm{Mn}: 25, \mathrm{Fe}: 26, \mathrm{Co}: 27, \mathrm{Ni}: 28, \mathrm{Cu}: 29$, $\mathrm{Zn}: 30)$