MCQ
All bond lengths are identical in :-
- A$PCl_5$
- B$ClF_3$
- ✓$NO_3^-$
- D$H_2SO_3$
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$\mathop {C{H_2} = CH - Br}\limits_{(I)} $ $\mathop {{\text{C}}{{\text{H}}_3} - Br}\limits_{\left( {II} \right)} $ $\mathop {\begin{array}{*{20}{c}}
{C{H_3} - CH - Br} \\
{|\,\,} \\
{\,\,\,C{H_3}}
\end{array}}\limits_{\left( {III} \right)} $ $\mathop {C{H_3}C{H_2}Br}\limits_{\left( {IV} \right)} $
Given $\mathrm{R}=8.31\, \mathrm{~J} \,\mathrm{~K}^{-1} \,\mathrm{~mol}^{-1} ; \log 6.36 \times 10^{-3}=-2.19$ $\left.10^{-4.79}=1.62 \times 10^{-5}\right]$