MCQ
Allyl phenyl ether can be prepared by heating
- ✓$C_6H_5Br + CH_2 = CH - CH_2 - ONa$
- B$CH_2 = CH - CH_2 - Br - C_6H_5ONa$
- C$C_6H_5 - CH =CH - Br - CH_3 - ONa$
- D$CH_2 =CH - Br - C_6H_5 - CH_2 - ONa$
✓
Answer
Correct option: A.
$C_6H_5Br + CH_2 = CH - CH_2 - ONa$
a
$C_6H_5Br + NaO - CH_2 - CH = CH_2$ $\longrightarrow$ $\begin{array}{l}
{C_6}{H_5} - O - C{H_2} - CH = C{H_2} + NaBr\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{Allyl\, phenyl\, ether}}
\end{array}$
$C_6H_5Br + NaO - CH_2 - CH = CH_2$ $\longrightarrow$ $\begin{array}{l}
{C_6}{H_5} - O - C{H_2} - CH = C{H_2} + NaBr\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{Allyl\, phenyl\, ether}}
\end{array}$
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