Download App

The p-Block Elements — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryThe p-Block Elements1 Mark
MCQ
Aluminium is much more reactive than iron because its standard reduction potential is higher than iron. Still, aluminium is less easily corroded than iron because :
  • A
    Aluminium reacts with atmospheric carbon dioxide to form a self$-$protective layer of $\ce{Al_2​O_3}$​.
  • ✓
    It has a higher reducing power and forms a self protective layer of $\ce{Al_2​O_3}$​​.
  • C
    it has a higher reducing power and does not react with oxygen so easily.
  • D
    both $A$ and $B.$
✓

Answer

Correct option: B.
It has a higher reducing power and forms a self protective layer of $\ce{Al_2​O_3}$​​.
Aluminium is much more reactive than iron because its standard reduction potential is higher than iron. However, aluminium is still less easily corroded than iron because oxygen forms a protective oxide layer of $\ce{Al_2​O_3}$​​ on its surfac.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from The p-Block Elements→The p-Block Elements — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

If coordinate $'X'$ is atomic number then select best for $'Y'$ coordinate 
→
Two hybrid orbitals have a bond angle of $120^o$. The percentage of $s-$ character in the hybrid orbital is nearly ............. $\%$
→
In which of the following pair, both the species are isoelectronic but the first one is  large in size than the second?
→
$\ce{H_2​O}$ is a:
→
 Bond line formula of  $HOCH$ $({CN})_2$  is: 
→
Structure of $3,4-$ dimethyl pent $-1-$ en $-3-$ ol is
→
Which of the following is the best example to demonstrate the law of conservation of mass?
→
After completion of $'np\ ’$ level, the electron enters into which level according to $\ce{(n + p)}$ rule?
→
The $IUPAC$ name of 

$\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {C{H_3} - CH - C{H_2} - C - C{H_3}} \\ 
  {\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,} 
\end{array}$ and $\begin{array}{*{20}{c}}
  {C{H_2} - CH - C{H_2}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,} \\ 
  {CN\,\,\,\,\,\,\,\,CN\,\,\,\,\,\,\,\,CN\,\,} 
\end{array}$

→
The energy of a photon is calculated by
→