$\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
H-C-D\xrightarrow[(50\%)]{H{{O}^{-}}} \\
\end{matrix}$ Product of this Cannizaro reaction is:
→The conductivity of a weak acid $HA$ of concentration $0.001\, \mathrm{~mol}\, \mathrm{~L}^{-1}$ is $2.0 \times 10^{-5}\, \mathrm{~S} \,\mathrm{~cm}^{-1} .$ If $\Lambda_{\mathrm{m}}^{\circ}$ $(\mathrm{HA})=190 \,\mathrm{~S} \,\mathrm{~cm}^{2} \mathrm{~mol}^{-1}$, the ionization constant $\left(\mathrm{K}_{\mathrm{a}}\right)$ of $\mathrm{HA}$ is equal to $....\,\times 10^{-6} .$ (Round off to the Nearest Integer)
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