- A$[Mn(H_2O)_6]^{3+}$
- ✓$[Fe(H_2O)_6]^{3+}$
- C$[Co(H_2O)_6]^{2+}$
- D$[Co(H_2O)_6]^{3+}$
$\Delta_{o}<$ pairing energy.
$\mathrm{CFSE}=(-0.4 x+0.6 y) \Delta_{o}$
where, $x$ and $y$ are no. of electrons occupying $t_{2 g}$ and es orbitals respectively.
For $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ complex ion.
$\mathrm{Fe}^{3+}\left(3 d^{5}\right) =t_{2 \mathrm{g}}^{3} e_{\mathrm{g}}^{2}=-0.4 \times 3+0.6 \times 2$
$=0.0 \text { or } 0\; \mathrm{Dq}$
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$(A)$ The total number of stereoisomers possible for ${X}$ is $6$
$(B)$ The total number of diastereomers possible for ${X}$ is $3$
$(C)$ If the stereochemistry about the double bond in ${X}$ is trans, the number of enantiomers possible for ${X}$ is $4$
$(D)$ If the stereochemistry about the double bond in ${X}$ is cis, the number of enantiomers possible for ${X}$ is $2$

$\mathrm{MnO}_4^{-}+\mathrm{H}^{+}+\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \rightleftharpoons \mathrm{Mn}^{2+}+\mathrm{H}_2 \mathrm{O}+\mathrm{CO}_2$
The standard reduction potentials are given as below $\left(\mathrm{E}_{\mathrm{red}}^{\circ}\right)$
$\mathrm{E}_{\mathrm{MmO}_4^{-} / \mathrm{Mm}^{2+}}^{\circ}=+1.51 \mathrm{~V}$
$\mathrm{E}_{\mathrm{CO}_2 / \mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4}^{\circ}=-0.49 \mathrm{~V}$
If the equilibrium constant of the above reaction is given as $K_{\text {eq }}=10^x$, then the value of $x=$____ (nearest integer)
