MCQ
Among the following ions the $p\pi - d\pi $ overlap could be present in
- A$NO_2^ - $
- B$NO_3^ - $
- ✓$PO_4^{ - 3}$
- D$CO_3^{ - 2}$
In nitrogen and carbon, no vacant $d$-orbital is present. So, they do not form $p \pi- d \pi$ bond.
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$(R = 8.314\,J\,{\rm{degre}}{{\rm{e}}^{{\rm{ - 1}}}}mo{l^{ - 1}})$
$\mathrm{PF}_5, \mathrm{BrF}_5, \mathrm{PCl}_5,\left[\mathrm{PtCl}_4\right]^{2-}, \mathrm{BF}_3, \mathrm{Fe}(\mathrm{CO})_5$
${I^ - }(aq.) + MnO_4^ - (aq.)\xrightarrow[{weakly\,\,O{H^ - }}]{{Neutral\,\,or}}Y + Mn{O_2}$
$MnO_4^ - (aq.) + M{n^{2 + }}(aq.)\xrightarrow{{ZnS{O_4}}}Z + 4{H^ + }$
Products $X,\,Y$ and $Z$ are respectively :