- Asec-butyl
- ✓ter-butyl
- Cn-butyl
- DNone of these
The higher the number of alkaline groups, the greater the charge is the deflection and hence the more carbonium ion is permanent.
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($R$ is gas constant)
$(A)\xrightarrow{{\operatorname{Re}duction}}(B)\xrightarrow{{HN{O_2}}}{C_2}{H_5}OH$
$\mathop {\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - C{H_2} - Cl}
\end{array}}\limits_{\left( I \right)} $ $\underset{(II)}{\mathop{\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\, \\
Cl-C{{H}_{2}}-C-H \\
\end{matrix}}}\,$
$\mathop {\begin{array}{*{20}{c}}
O \\
{||} \\
{H - C - H}
\end{array}}\limits_{\left( {III} \right)} $ $\mathop {\begin{array}{*{20}{c}}
O \\
{||} \\
{{H_3}C - C - C{H_3}}
\end{array}}\limits_{\left( {IV} \right)} $
[Given $: R =8.31 \,J \,K ^{-1} \,mol ^{-1}, \log 1.33=0.1239$ $\ln 10=2.3]$