MCQ
Amongst the following, the compound that can be most readily sulphonated is
- ABenzene
- BNitrobenzene
- ✓Toluene
- DChlorobenzene
✓
Answer
Correct option: C.
Toluene
c
Toulene can be most readily sulfonated because of the electron releasing group attached to it. Nucleophilicity increases resulting in a fast attack to $E ^{\oplus}$ (during sulphonation).
Toulene can be most readily sulfonated because of the electron releasing group attached to it. Nucleophilicity increases resulting in a fast attack to $E ^{\oplus}$ (during sulphonation).
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Name the hydrocarbon that is a liquid at $STP$
→For the electrophilic substitution reaction involving sulphonation, which of the following sequence regarding the rate of reaction is true ?
The equivalent conductance of benzoic acid is $12.8\, ohm^{-1}\,cm^2\,eq^{-1}$. If conductance of benzoate ion and $H^+$ ion at infinite dilution is $42$ and $288.42\, ohm^{-1}\, cm^2$ respectively. Its degree of dissociation is ............. $\%$
→The occurrence of a reaction is impossible if
$Me_2C=CH-CH_2-CH_2-Cl \mathop {\xrightarrow{{{H_2}O}}}\limits_{CaC{O_3}} (X)$
→Major product of above reaction is
The $\Delta H^o_f$ for $CO_2(g) , CO(g)$ and $H_2O(g)$ are $-393.5, -110.5$ and $-241.8\, kJ/mol$ respectively, the standard enthalpy change (in $kJ$) for the reaction
$CO_2(g) + H_2(g) \to CO(g) + H_2O(g)$ is :
→$CO_2(g) + H_2(g) \to CO(g) + H_2O(g)$ is :
The dissociation of $SO_3(g)$ into $SO_2(g)$ & $O_2(g)$ is carried out in a closed container at a constant temperature $T$ . The equilibrium constant for the reaction is $K_P$ = $x\ atm^2$ . The partial pressure variation for the three gases is as shown
→The value of $x$ is
$XeF_6$ on partial hydrolysis with water produces a compound $'X'$. The same compound $'X'$ is formed when $XeF_6$ reacts with silica. The compound $'X'$ is
→Assertion : The radius of the first orbit of hydrogen atom is $0.529\,\mathop A\limits^o$
Reason : Radius of each circular orbit $(r_n) - 0.529\,\mathop A\limits^o \,(n^2/Z),$ where $n = 1, 2, 3$ and $Z =$ atomic number.
→Reason : Radius of each circular orbit $(r_n) - 0.529\,\mathop A\limits^o \,(n^2/Z),$ where $n = 1, 2, 3$ and $Z =$ atomic number.
In the reaction $Image$ the structure of the Product $T$ is
→