- AAddition
- ✓Substitution
- CDehydrohalogenation
- DElimination
$\underset{Alkyhalide}{\mathop{R-\,C{{H}_{2}}-C{{H}_{2}}-X}}\,\xrightarrow[Alc.KOH]{Dehydroha\log enation}$ $\underset{Alkene}{\mathop{R-\,CH=C{{H}_{2}}+HX}}$
$\underset{Alkyhalide}{\mathop{R-\,C{{H}_{2}}-C{{H}_{2}}-X}}\,\xrightarrow[Alc.KOH]{E\lim ination}$ $\underset{Alkene}{\mathop{R-\,CH=C{{H}_{2}}+HX}}$
$\underset{Alkyhalide}{\mathop{R-\,C{{H}_{2}}-C{{H}_{2}}-X}}\,\xrightarrow[substitution]{Aq.\,KOH}$ $\underset{Alcohol}{\mathop{R-\,C{{H}_{2}}-C{{H}_{2}}-OH+HX}}\,$
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(At. nos. $Ti = 22,\,Cr = 24,$ $ Mn = 25,\,Ni = 28$)
$(a)$ Number of $S-S$ bonds in $H_2S_nO_6$ are $(n +1)$
$(b)$ When $F_2$ reacts with $H_2O$ it forms $HF,$ $O_2$ & $O_3.$
$(c)$ $XeF_6$ on hydrolysis shows disproportionation reaction
$(d)$ $Al$ metal on reacting with dilute $NaOH$ gives a white precipitate of $Al (OH)_3$ as a final product
$(I) \,S _{2} O _{4}^{2-}$
$(I I)\, S _{2} O _{5}^{2-}$
$(III) \,S _{2} O _{6}^{2-}$
Statement I : $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ is a homoleptic complex whereas $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]^{+}$is a heteroleptic complex.
Statement II : Complex $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ has only one kind of ligands but $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]^{+}$has more than one kind of ligands.
In the light of the above statements, choose the correct answer from the options given below.