MCQ
An anion solution gives a white ppt. With $AgN{O_3}$ solution. The ppt. dissolves in dil. ammonia due to the formation of
  • A
    $AgN{O_3}$
  • B
    $N{H_4}N{O_3}$
  • $\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]Cl$
  • D
    $\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]Br$

Answer

Correct option: C.
$\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]Cl$
c
(c) $AgN{O_3} + C{l^ - } \to AgCl + NO_3^ - $

$AgCl + 2N{H_3} \to \mathop {[Ag{{(N{H_3})}_2}]Cl.}\limits_{{\text{diammine silver (I) chloride}}{\text{.}}} $

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