Chemistry in Everyday Life — Chemistry STD 12 Science — Question

$(A)\,{{C}_{8}}{{H}_{10}}\xrightarrow{KMn{{O}_{4}}}(B){{C}_{8}}{{H}_{6}}{{O}_{4}}\xrightarrow[Fe]{B{{r}_{2}}}{{C}_{8}}{{H}_{5}}Br{{O}_{4}}(C)$ (one-product only)

$\left[\mathrm{CoCl}\left(\mathrm{NH}_3\right)_5\right]^{2+}, \quad\left[\mathrm{Co}(\mathrm{CN})_6\right]^{3-} \text {, }$

$(A)$                                        $(B)$

$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{H}_2 \mathrm{O}\right)\right]^{3+}, \quad\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_4\right]^{2+}$

$(C)$                                       $(D)$

The correct order of $A$, $B$, $C$ and $D$ in terms of wavenumber of light absorbed is :

$X \left| X ^{2+}(0.001 M ) \| Y ^{2+}(0.01 M )\right| Y$

is $.......\times 10^{-2} V$ (Nearest integer).

Given: $E _{ x ^{2+} \mid x }^0=-2.36\,V$

$E _{ Y ^{3+} \mid Y }^0=+0.36\,V$

$\frac{2.303\,RT }{ F }=0.06\,V$

$Z\xrightarrow{{PC{l_5}}}X\xrightarrow{{Alc.KOH}}Y\xrightarrow{{dil{H_2}S{O_4}}}Z$