- A$56$
- B$550$
- ✓$5.6$
- D$11.2$
$2 O^{2-} \rightarrow O_{2}+4 e^{-}$
$4 A g^{+}+2 O^{2-} \rightarrow O_{2}+4 A g \ldots( i )$
Amount of silver generated $=0.108 g$ No. of mole of $A g=\frac{0.108}{108}=0.001 mole$
No. of mole of $O_{2}$ generated from equation (i) $\frac{0.001}{4}$
$\begin{aligned} \text { volume of } O_{2} =\frac{0.001}{4} \times 22.4 \times 10^{3} cm ^{3} \\ =5.6 cm ^{3} \end{aligned} $
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$A\xrightarrow[{(ii)\,\,Conc.\,{H_2}S{O_4}/\Delta }]{{{\text{(i)}}\,{\text{C}}{{\text{H}}_3}MgBr/{H_2}O}}$
$B\xrightarrow[{(ii)\,Zn/{H_2}O}]{{(i)\,{O_3}}}C + D$
$D\xrightarrow[\Delta ]{{Ba\left( {OH} \right)}}\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {{H_3}C - C} \end{array}$$\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,O} \\ {\,\,\,\,\,||} \\ { = CH - C - C{H_3}} \end{array}$
