Question
An electric dipole is placed inside a closed surface, whose dipole moment is $20 \times 10^{-6}$ coulomb$-$meter. What will be the electric flux emerging out of this surface?
✓
Answer
There are charge of equal magnitude and opposite nature at the ends of the electric dipole.
Therefore, the total charge $q$ inside the closed surface will be zero.Therefore, according to Gauss' theorem, the electric.
Therefore, $ \phi=\frac{q}{\epsilon_0}=0$
$\phi=\text { zero } $
Therefore, the total charge $q$ inside the closed surface will be zero.Therefore, according to Gauss' theorem, the electric.
Therefore, $ \phi=\frac{q}{\epsilon_0}=0$
$\phi=\text { zero } $
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