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2. Electric potential and capacitance — Physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 SciencePhysics2. Electric potential and capacitance1 Mark
MCQ
An electron enters between two horizontal plates separated by $2\,mm$ and having a potential difference of $1000\,V$. The force on electron is
  • A
    $8 \times {10^{ - 12}}\,\, N$
  • ✓
    $8 \times {10^{ - 14}}\,\, N$
  • C
    $8 \times {10^9}\,\, N$
  • D
    $8 \times {10^{14}}$ $N$
✓

Answer

Correct option: B.
$8 \times {10^{ - 14}}\,\, N$
b
(b) Force on electron $F = QE$ $ = Q\,\left( {\frac{V}{d}} \right)$
$⇒$ $F = (1.6 \times {10^{ - 19}})\,\left( {\frac{{1000}}{{2 \times {{10}^{ - 3}}}}} \right) = 8 \times {10^{ - 14}}\,N$

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