MCQ
An electron of mass $m$ when accelerated through a potential difference $V$ has de-Broglie wavelength $\lambda$. The de-Broglie wavelength associated with a proton of mass $M$ accelerated throug the same potential difference will be
  • A
    (a) $\lambda \frac{m}{M}$
  • (b) $\lambda \sqrt{\frac{m}{M}}$
  • C
    (c) $\lambda \frac{M}{m}$
  • D
    (d) $\lambda \sqrt{\frac{M}{m}}$

Answer

Correct option: B.
(b) $\lambda \sqrt{\frac{m}{M}}$
(b) $\lambda=\frac{h}{\sqrt{2 m E}} \Rightarrow \lambda \propto \frac{1}{\sqrt{m}} \quad(E=$ same $)$

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