MCQ
An equimolar solution of $\ce{NaNO_2}$ and $\ce{HNO_2}$ can act as a:
- AStrong reductant.
- BStrong oxidant.
- ✓Buffer solution.
- DNone of these.
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${I^ - }(aq.) + MnO_4^ - (aq.)\xrightarrow[{weakly\,\,O{H^ - }}]{{Neutral\,\,or}}Y + Mn{O_2}$
$MnO_4^ - (aq.) + M{n^{2 + }}(aq.)\xrightarrow{{ZnS{O_4}}}Z + 4{H^ + }$
Products $X,\,Y$ and $Z$ are respectively :

